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Proceedings of the 19th Conference on Computer Science and Intelligence Systems (FedCSIS)

Annals of Computer Science and Information Systems, Volume 39

Secretary problem revisited: Optimal selection strategy for top candidates using one try in a generalized version of the problem

DOI: http://dx.doi.org/10.15439/2024F3882

Citation: Proceedings of the 19th Conference on Computer Science and Intelligence Systems (FedCSIS), M. Bolanowski, M. Ganzha, L. Maciaszek, M. Paprzycki, D. Ślęzak (eds). ACSIS, Vol. 39, pages 719724 ()

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Abstract. This paper explores a novel variation of the classical secretary problem, commonly referred to as the marriage or best choice problem. In this adaptation, a decision-maker sequentially dates $n \in \mathbb{N}$ candidates, each uniquely ranked without ties from $1$ to $n$. The decision strategy involves a preliminary non-selection phase of the first $d \in \mathbb{N}$ candidates where, $d < n$, following which the decision-maker commits to the first subsequent candidate who surpasses all previously evaluated candidates in quality. The central focus of this study is the derivation and analysis of $P(d, n, k)$, which denotes the probability that the selected candidate, under the prescribed strategy, ranks among the top $k \in \mathbb{N}$ overall candidates, where $k \leq n$. This investigation employs combinatorial probability theory to formulate $P(d, n, k)$ and explores its behavior across various parameter values of $d$, $n$, and $k$. Particularly, we seek to determine in what fraction of the entire decision process should a decision-maker stop the non-selection phase, i.e., we search for the optimal proportion $\frac{d}{n}$, that maximizes the probability $P(d, n, k)$, with a special focus on scenarios where $k$ is in generally low. While for $k = 1$, the problem is simplified to the classical secretary problem with $\frac{d}{n} \approx \frac{1}{e}$, our findings suggest that the strategy's effectiveness is optimized for portion $\frac{d}{n}$ decreasing below $\frac{1}{e}$ as $k$ increases. Also, intuitively, probability $P(d, n, k)$ increases as $k$ increases, since the number of acceptable top candidates increases. These results not only extend the classical secretary problem but also provide strategic insights into decision-making processes involving ranked choices, sequential evaluation, and applications of searching not necessarily the best candidate, but one of the best candidates.

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